Finally someone who agrees it's not 1!
math
Sort:
ActivatePlan357 wrote:
Yes Mikey...same proof I did in post #70
i didn’t see your post
i remember seeing the proof we borh did somewhere outside of chess.com. (i can’t remember where tho)
No worries Mikey, it is a common proof that I cannot take credit for. I was just pointing out the fact that I was not the only one to prove it that way to solidify that the proof is accurate. Thus reinforcing the fact that 1 = 0.999... is true. In fact, someone else posted the same proof before me. It wasn't as elegant but it was acceptable.
The expression 0.999... should be interpreted as the limit of the sequence 0.9, 0.99, 0.999, ... and so on. This sequence can be rigorously shown to have the limit 1, and therefore this expression is meaningfully interpreted as having the value 1.[7] copied from https://en.m.wikipedia.org/wiki/Limit_(mathematics)
Um, if you would add any number above zero (because zero is infinitely small),
to 0.(9) It would be greater than one so, theoretically 0.(9) is neither equal to one or less than one.
to 0.(9) It would be greater than one so, theoretically 0.(9) is neither equal to one or less than one.
And, 1 + 0.(9) will not equal 2 without rounding, and rounding is not an exact formula.
To think that this math debate started with Chessguy2 commenting “I just wanted to say 1=.9 repeating, any one differ?”
Based on your post Ellem stating zero is infinitely small, then 1 - 0.999... = 0.000... = 0 (because zero is infinitely small). Therefore 0.999... = 1
Btw percents can be swapped. For example: 6% of 50 is actually 50% of 6 which is a lot easier to calculate.
#129 that works with select few numbers. 10% of 1 = 0.1 but, 1% of 10 = 1. 5% of 10 = 2 but 10% of 5 = 0.5
Please Sign Up to comment.
If you need help, please contact our Help and Support team.
So what happened with 1 and 0.(9)?
I shall answer this;
Just as 9, 99, 999 etc. Does not become (10^n) for natural number n, 0.9, 0.99, 0.999 etc. Never becomes the number 1!