Weakest Group

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artfizz

Which is the weakest group (in terms of Average Rating) on chess.com?

Why is Average Rating not displayed for some groups?

 

It would be very helpful if Average Rating could be added as a sort key on Group Search - alongside the existing sort keys:  # of MembersDate Formed and Alphabetical.

This would make it easier to find groups with compatible strengths when setting up Team Match challenges. This should lead to fairer matches  (http://www.chess.com/forum/view/help-support/first-come-first-served-team-chess).

http://www.chess.com/forum/view/chess-players/teams

 

lilybetrice

Well said Arty!

artfizz

Just Like That

 Average Rating 984

(Coincidentally, Just Like That - a small group of beginners - is looking for some weak opposition - to bolster their confidence! and learn the game. Any takers for a Team Match with a rating maximum of around 1111?)

Keyif

Very good idea.

ncpharaoh

i agree, good idea

ncpharaoh

off topic, art who is that in the photo?

artfizz
ncpharaoh wrote: off topic, art who is that in the photo?

Tommy Cooper - magician renowned for getting his tricks wrong

artfizz

No group has come forward claiming to be weaker than Just Like That (Avg Rating now a little stronger at 998).

A question for you: suppose there are two groups, A & B, with the same average rating. Further suppose group A has twice as many members as group B.

Which is the weaker group?

SALICRUP

okLaughing

ncpharaoh
artfizz wrote:
ncpharaoh wrote: off topic, art who is that in the photo?

Tommy Cooper - magician renowned for getting his tricks wrong


 funny, thx art

artfizz
paul211 wrote:

art post #8

I believe that you are asking what group has the better chance of winning games.

If 2 players of equal strength, your premisse as you did not give any distribution of the player's ratings, play together the chance of winning is 50/50.

If 4 players of equal strength play 2 by 2 on 2 different boards, since the events are independant, meaning that the result of game one has no influence on the result of game 2, then the probality of winning or loosing is 1/2*1/2 or 25%.

I believe that using induction, one can calculate the probality of any team size winning the competition.


Assume, for the sake of argument, that group A has 12 members and group B has 6 members. Assume that player ratings are normally distributed, that the average team size is 4, and that teams are selected randomly.

For example, take these two specific groups.

Group A

Group B

1130

 

1205

1250

1319

 

1325

1356

1409

 

1447

1442

1543

 

1544

1472

1567

 

1567

1481

1610

 

1734

1699

 

 

Average = 1450

Average = 1450

On average, which group is going to field the stronger team i.e. the one with the greater average rating?