Chess will never be solved, here's why

Missed this one before.  Ummm, yes I am aware.  I've been posting here for a decade and I quote and then edit every reply I make to remove excess nested comments (with very few exceptions).  It's certainly annoying, but not particularly complex.

They used some form of TinyMCE-like free source code to create the editor, and it has not received much love over the years.  The analysis editor added on is by the far the most work.

     To quote American humorist Foghorn Leghorn; "That's a joke son. I say that's a joke." Not meant to be taken seriously. Only pointing out how ridiculous some comments here have been.

     Exactly. You already have the conclusion and make sure you don't investigate enough possibilities to risk finding out it may be incorrect.

     One man's "thoughtful" is another man's "arbitrary". Your arbitrary selection of likeminded "experts" to cull the lines to be examined by  admittedly imperfect machines cannot produce something that many people will consider a believable solution.

     As you have often expressed the opinion here that unassailable proof on these points is either impossible to obtain or lies countless years in the future you would face financial ruin.

     I do agree with you on both points but you won't be able to produce any proof that will convince doubters to pay up.

Someone show an advantage for Black, here;

https://www.365chess.com/opening.php?m=10&n=347&ms=e4.e5.Nf3.Nc6.Bb5.Nf6.d4.Nxe4.O-O&ns=3.5.5.6.5.273.1722.18420.347

Howdy ha!

A multiple of 100 is reached by Me, yet again!

I'll take your bet that 1. e4 e5 2. Ba6 loses for white at odds of 10^24 to 1.  How much do you want to stake?

thats making an assumption that black's moves are perfect/good.  also, you need to calculate moves by black in response to white moves that differ from the seed.  

"Probably 1 e4 e5 and 1 e4 c5 draw as well,
but we only need one to weakly solve Chess, so the other is not relevant."

actually no, both are relevant, because you dont know which one draws, wins, or loses. you choose one, and if that one fails, you have to check the other.  but you cant gaurentee that the first one you choose works

tygxc you are also still assuming a draw.  

my GUESS is a draw.  it hasnt yet been proven, though.

its extremely statistically likely.  

     Most of us, myself included, agree it's a draw, but also realize that neither the strongest human players nor the best contemporary engines can irrefutably demonstrate that this is true.

Asserting anything about the distant future is wholly misguided, with the exception of this statement.

     The only constant is change. Mais, plus sa change, plus c'est la meme chose.

@8203

"making an assumption that black's moves are perfect/good"
++ No assumption is needed:
it becomes certain when the black moves lead to a 7-men endgame table base draw,
or a prior 3-fold repetition.

@8204

"both are relevant, because you dont know which one draws, wins, or loses. you choose one,
and if that one fails, you have to check the other"
++ No: the grandmasters chose the best candidate to draw as black disregarding all alternatives. If a 7-men endgame table base draw or a 3-fold repetition is reached in all lines,
then in retrospect the selected black move was right.
Yes, if 1 e4 e5 were to fail, then 1 e4 c5 would have to be checked, but that is not realistic.
You cannot find any white win after 1 e4 e5.

@8208

"hikaru says also draw but he is very confident. when they asked he says we just know it"
++ 'That ... every even integer is a sum of two primes,
I regard as a completely certain theorem, although I cannot prove it.' - Euler
Still considered true, still unproven.