Diaprove this
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Lol Hfl Zeroth comes
Hmmm
Oct 3, 2023
0
#4
1E3E52KE2 wrote:
I have two simultaneous equations:
x+3y=1 and y=5-x
So replace y with 5-x, I have:
3x+3(5-x)=1
=3x+15 -3x=1
=3x-3x+15=1
=0+15=1
Then 15=1???
Can someone disprove this?
x+3y=1 and y=5-x
So replace y with 5-x, I have:
3x+3(5-x)=1
=3x+15 -3x=1
=3x-3x+15=1
=0+15=1
Then 15=1???
Can someone disprove this?
You just arbitrarily changed x to 3x. You can't do that...
QED
I CAN DO ANYTHING
x = two quadrillion
x = two quadrillion
lol I suck too much in algebra to do dis
If you hadn’t randomly turned x into 3x, you would’ve eventually simplified to -2x=-14, meaning x= 7.
This also means y=-2, since substituting x with 7 in the original equation makes it 5-7, which is -2.
here is another challenge
7^0 = 1
3^0 = 1
so 3 = 7
disprove this
x+3y=1 and y=5-x
So replace y with 5-x, I have:
3x+3(5-x)=1
=3x+15 -3x=1
=3x-3x+15=1
=0+15=1
Then 15=1???
Can someone disprove this?