If 0^0 is equal to 1, and only 1...

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One_Zeroith

Then 0^(0-1) shall be equal to 1/0.

And 0^(0+1) shall equal 0/1

Therefore ((0^(0-1))*((0^(0+1)) does equal 0^0 as well as it does (0/0) which is not only 1.