'Almost' is not a math term.
math
Because 1=1
so
1 cannot = .9 repetitive
A mathematical value cannot have multiple value's, because it is a single value.
I know this is 13 years old, but lol... has no concept of what the = symbol means.
10 * 0.999999... = 9.999999 = 9 + 0.999999...
9 * 0.999999... = 9
0.9999999... = 1
That's not a logical progression... how do you get the 2nd line?
I think the easiest example for kids is this...
Do 1/9 by hand (or use a calculator) and you get 0.11111...
Now do 2/9 and you get 0.22222
.
.
.
7/9 = 0.777...
8/9 = 0.888...
9/9 = 0.999...
Wait, but 9/9 = 1 ![]()
Nope Gentlemen (and Ladies too, if any!)
999...ad infinitum does not equal 1-0-0...000 ad infinitum. But (999...ad infinitum)-1, not 0 !
0.999... does not equal 1.000...
Name a number in between the two.
Or, for example, subtract the two. You would get 0.0000... and the zeros go on forever, so it's just zero, so the two numbers are equal because subtracting them = 0.
The final digit of an irrational number is Infinitesimal, but not equal to 0.
Likewise the final digit of 9, 99, 999 finishes at (10^1)-1, but never becomes 10-0, just always (10^n)-1.
Make sense??
I just wanted to say 1=.9 repeating, any one differ?
While the two values have a value that seems the same, I believe that the 2 values are slightly different. This argument is similar to asking if infinity is 1/0. While if you approximate both sides they look the same, if you set them equal to each other there are some fundamental flaws. If you believe in completed infinity, then you would think that they are the same, but if you did not believe in infinity, and believe in approaching infinity, you would see that .9 repeating approaches 1, but never equals 1. The algebraic proofs hinge on the fact that .1 repeating = 1/9, so .9 repeating = 1, but they are never equal. Just approaching. Even though repeating states that the decimal goes on forever, it is more like approaching 1/9, like my infinity analogy.
They are not equal, just approaching each other.
But*