Riddles for fun

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sid0049

Yes happy.png

Ugghhh... you get all of them.

Do you know the second answer?

 

IcyAvaleigh

yeah well everyone goes to the hairdresser so...happy.png I do not know the second one though :/ I guess a doctor? when they have to amputate a part of your body or so? 

big_big_poo

?

sid0049

Yes, surgery in a hospital happy.png

big_big_poo

cool

big_big_poo

uh

big_big_poo

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IcyAvaleigh

In a room with cats and dogs, each cat sees as many cats as dogs. Each dog sees half as many dogs as cats. 

How many cats and dogs are there in the room?

sid0049

4 cats, 3 dogs

IcyAvaleigh

Correct but tuggy was faster sorry ;P

sid0049

Meh its fine haha

Is it possible to solve this with math equations?

sid0049

a punching bag?

IcyAvaleigh
tuggypetu wrote:

Meh its fine haha

Is it possible to solve this with math equations?

c-1= d because each cat sees as many dogs but not themselves

d-1= 0.5c because each dog sees half as many dogs as cats but not themselves (means d= 0.5c + 1)

So you can say c-1=0.5c+1 multiplied by 2 gives 2c - 2= c+ 2

This gives c-4=0 so c=4!!! It is possible xD

IcyAvaleigh

Oh a teacher? XD

IcyAvaleigh

oh so true I hate the sounds of them 😂

sid0049
IcyAvaleigh wrote:
tuggypetu wrote:

Meh its fine haha

Is it possible to solve this with math equations?

c-1= d because each cat sees as many dogs but not themselves

d-1= 0.5c because each dog sees half as many dogs as cats but not themselves (means d= 0.5c + 1)

So you can say c-1=0.5c+1 multiplied by 2 gives 2c - 2= c+ 2

This gives c-4=0 so c=4!!! It is possible xD

nice

sid0049
VibhanshAlok wrote:

Well it’s an alarm clock. But other answers are also true in other way round 😆 

nice one. first one icy didnt get on this forum happy.png haha

IcyAvaleigh

grrrr ;/ 

sid0049

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