What is 2^(1-infinity)??

It is 2/(2^infinity)

Which is 1/infinity. But is not 0.

Infinity is not a number

It can be computed and operated with, in Mathematical equations.

https://en.m.wikipedia.org/wiki/Infinitesimal

1/infinity=an Infinitesimal, is.

In mathematics, an infinitesimal number is a quantity that is closer to zero than any standard real number, but that is not zero. The word infinitesimal comes from a 17th-century Modern Latin coinage infinitesimus, which originally referred to the "infinity-th" item in a sequence.

Infinitesimals (ε) and infinities (ω) on the hyperreal number line (ε = 1/ω)
Infinitesimals do not exist in the standard real number system, but they do exist in other number systems, such as the surreal number system and the hyperreal number system, which can be thought of as the real numbers augmented with both infinitesimal and infinite quantities; the augmentations are the reciprocals of one another.

Infinitesimal numbers were introduced in the development of calculus, in which the derivative was first conceived as a ratio of two infinitesimal quantities. This definition was not rigorously formalized. As calculus developed further, infinitesimals were replaced by limits, which can be calculated using the standard real numbers.

Infinitesimals regained popularity in the 20th century with Abraham Robinson's development of nonstandard analysis and the hyperreal numbers, which, after centuries of controversy, showed that a formal treatment of infinitesimal calculus was possible. Following this, mathematicians developed surreal numbers, a related formalization of infinite and infinitesimal numbers that include both hyperreal cardinal and ordinal numbers, which is the largest ordered field.

I've theorized that numbers such as infinity+1/infinity, are infinite and infinitesimal quantity sums.

While

Infinity+(-1)^0.5 is an imaginary infinite number!

No

Is (1/♾️)^-1 equal to +♾️

Yes.

But it is not -infinity as well, which 1/0 is; as a limit to when 1/x tends to +/-infinity as x approaches 0 from either side.

1/0 is not infinity, infinity is not a number. 1/0 is undefined.

So is 2^(infinity-1)=infinity/2 then?

Nope. It's, (2^infinity=infinity)/2

1/0 is even greater than infinity itself.

For 1/1/(1/infinity) is just 1/infinity. While 1/(1/0) is 0.- Less.

gotta agree with this one, infinity manages to break many principles and can't be classified into 1 category, such as integer or natural. So it can't possibly be a number.

Then neither is a Rational number fraction, or Irrational number, D *ofus

Infinity+(-1)^0.5 can be defined as a number.

1-inf. = İnf.. So this means 2^minus infinity.. which equals a value that approaches zero but is not 0, in practice we can take this to be 0, but when graphing we can never take it to be 0

Yes, pretty true, Sir