What is ∞/∞ ?
Ok, Old Q*een. Of Nothing!
Your language makes me suspect that your education has been very minimal due to the rough language you use. This makes me believe that your math skills are as roughly the same. Beware of your language and what it can make others assume about you.
I know better. You apparently do not.
You are failing horribley at conveying the "Universal Language." Which I am like a Master at!
Nope, I learned about the "Indeterminate Forms" from a College Text book I read in 9th Grade, before Google.
If you are not sure about something I am posting, no shame in Googling it, though.
How far have you gotten in your mathematical career? Geometry? Trigonometry? College?
I read a college calculus book.
What have you read to arrive at these non sense postings?
If you argued like this as a private attorney, you would find no clients. Worse in Chess.
A college textbook? When was this textbook made? And who was it written by?
Don't remember. But it has served me quite excellently.
I studied math through top professors and I’ve had to learn a lot of theorems and formulas for my career.
Then convey them more intelligently, Sir.
For any positive integer n:
If n is odd, n = 3n+1
If n is even, n = n/2
Is there a positive integer that cannot return 1 through this function?
For any positive integer n:
If n is odd, n = 3n+1
If n is even, n = n/2
Is there a positive integer that cannot return 1 through this function?
I swear this is like the third time I'm hearing this riddle.
If 3^x is 0 then what is x?
For any positive real number (such as 3), raising it to any power (including x) will always result in a positive value (except for 0 raised to any power, which is always 1).
Therefore, the equation 3^x = 0 cannot be true for any real number value of x. The statement 3^x = 0 is mathematically undefined.
x would be -infinity.
You failed once again.
If 3^x is 0 then what is x?
For any positive real number (such as 3), raising it to any power (including x) will always result in a positive value (except for 0 raised to any power, which is always 1).
Therefore, the equation 3^x = 0 cannot be true for any real number value of x. The statement 3^x = 0 is mathematically undefined.
x would be -infinity.
You failed once again.
Infinity isn't a real number, to be fair.
If 3^x is 0 then what is x?
For any positive real number (such as 3), raising it to any power (including x) will always result in a positive value (except for 0 raised to any power, which is always 1).
Therefore, the equation 3^x = 0 cannot be true for any real number value of x. The statement 3^x = 0 is mathematically undefined.
x would be -infinity.
You failed once again.
Infinity isn't a real number, to be fair.
It may not be. But it is the approximate answer to that problem.
∞/∞ = any positive real number or just infinity (like #3 and #4 said)
Because ∞ *(+x ) = ∞ and ∞*∞ = ∞
Thanks. Cool