What is the Square Root of ♾️,+♾️ i?

i being the square root of -1, also called "the imaginary unit."

It would be;

(Infinity+i)*(infinity+i) which is equal to infinity+infinity i+infinity i-1=infinity+infinity i 

Their is no such equation that is allowed. Their is only infinity. You can not add or multiply infinity because infinity is already infinity. You cannot have infinity squared. And that is what your equation is asking for. The answer is this; try the checksum on your question and let your wisdom shine through.

If their is infinite universes, then their is a universe with another you in it, even ones with another you doing the same thing you are doing now, and further so, worlds where other worlds have exactly the same amount of people and the same people may be or may not be doing the same things. But in infinity, their is no limitations. A monkey will type out Shakespearian novels, if it is done infinite times.....etc., etc. Infinite knows no boundaries. 

Yet, what is (infinity+infinity i)^2

It is (infinity+Infinity i)*(infinity + infinity i) 

which is;

Infinity+infinity i+infinity i-infinity WHICH is indeterminate.

Nope, Read this.

http://www.maeckes.nl/Imaginair%20oneindig%20GB.html#:~:text=Mathematics%20has%20the%20concept%20of,nobody%20who%20really%20can%20imagine./

Mathematics has the concept of imaginary infinity. It is written as +∞ i and −∞ i.

First of all, we don't know what infinity is. That may sound strange, but there is nobody who really can imagine. Mathematicians don't care about that.

 
Explanation
A complex number can geometrically be represented by a point in the complexe plane. That consists of a real x-axis and orthogonal to that the imaginary y-axis. The x-axis runs from −∞ to +∞ and the y-axis from −∞ i to +∞ i.

 
Example 1
The hyperbolic tangent of an imaginary number can be converted to the tangent with

tanh (ix) = i tan (x)
For the special value ½πi you get ♾️ i.

True but it has no practical utility.

This is what destroyed Cantor's mind.

Nope, it was being tormented by Leopold Kronecker, and those that agreed with him.

Similarly what happened to Paul Morphy when Howard Staunton would not play him.

He retired to the US as undisputed master of his time.

You aren't serious, Dude?

2 pointless, inane posts in a row from you.

Sorry Chess.com, if that appeared to be flaming.

But anyone can see how how inane those 2 posts above, were.