is this possible (test)

1n6/1p1bkppp/1qpppnrr/2b5/p4K1P/RRNPBNP1/PPPQPPB1/8 w KQkq - 0 1

No, it is not!

The only way for the White Rooks to get out is via h3 with the White pawns where they are and nothing captured.  White would have to have played Rh1-h3-g3-g4-b4-b3-a3.  The Kingside Rook could do that.  The Queenside Rook could not have gotten out.  The only way for the Bishop on f1 to get out of White's way was to push g3 and get the Bishop to g2.  At this point, there is no way that the other Rook that started on a1 got out.

Black's piece arrangement is possible, but not White's!

Move the White h-pawn from h4 to h5 and it's possible.

Move either White Rook to somewhere behind the pawn chain, including h3, and it's possible.

By the way, if you are wondering how the White King got out and the Black Rooks across without checking the White King, the Black Knight went to e4, and the Black rooks then took their path to h6 and g6.  Then the Knight would have gone back to f6.

yes it is but unlikely

Prove it!  How does White get the second Rook out?  The one that started on a1?  The rest of it I buy.  As mentioned, move the a3 or b3 Rook to h3 and it's possible.  Or move the h-pawn to h5 and it's possible.

However, what you have is physically impossible with the combination of the Rook on a1 and the Bishop on g2.  There is no way to get the Rook on a1 outside the pawn chain until g3 and Bg2 are played, and it's impossible to get the Rook out AFTER g3 has been played.  So the h1-Rook can get there (before g3 is pushed), but the a1 Rook cannot unless you prove it!

I was dumb then