However
(0/infinity-0/infinity) shall equal, (infinity*0-infinity*0)/(infinity*infinity) which is indeterminate.
(1/infinity)-(1/infinity) Differs from (1-1)/infinity. Part 2
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(1/infinity)-(1/infinity) will equal, (1*infinity-1*infinity)/infinity which is intermediate.
While (1-1)/infinity is simply 0/infinity, which is simply 0 !