(a+b)^3

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Avatar of SriyoTheGreat

Today I was just chilling in school but for some reason I felt smart so I decided to derive a formula for (a+b)^3. This I failed at, but in the process I found an even more interesting pattern. 

Here it is :

 where n is the number of whole numbers present between a and b +1

If a≠b and b > a

(a+b)^3 = [[{b*(a+b)}^2] - [{a*(a+b)}^2]]/n

If a≠b and a > b

(a+b)^3 = [[{a*(a+b)}^2] - [{b*(a+b)}^2]]/n

Here is how you would write it in paper : 

unfortunately, this doesn't work when a = b, but I find it fascinating how the difference of squares of two different numbers (divided by n) can result in the cube of another number. Math is fascinating

Avatar of shadowhb123
Omg ur handwriting is horrendous we’re twins
Avatar of SriyoTheGreat
shadowhb123 wrote:
Omg ur handwriting is horrendous we’re twins

lol, writing using a touchpad is hard

Avatar of sumxr_txme

This reminded me that I have an algebra test today in first period

Avatar of Zestythefifth
😂 good reminder
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bump

Avatar of SriyoTheGreat
sumxr wrote:

This reminded me that I have an algebra test today in first period

well good luck

Avatar of SriyoTheGreat

Bump

Avatar of wow

eee

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im getting the test back on wednesday

Avatar of Lizunchikk
nice
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sumxr wrote:

im getting the test back on wednesday

Yo good luck