Let [1, 2, 3, 4…] be an infinite set called A
Subtract three from it.
[ 4, 5, 6, 7…] and say it is called B
Therefore
B-A=3
You can subtract X numbers and keep on going
[X, X+1, X+2, X+3…]
How ♾️ - ♾️ differs from ♾️*0
Sort:
Another way to think of it would be with sets.
Let [1, 2, 3, 4…] be an infinite set called A
Subtract three from it.
[ 4, 5, 6, 7…] and say it is called B
Therefore
B-A=3
You can subtract X numbers and keep on going
[X, X+1, X+2, X+3…]
Let [1, 2, 3, 4…] be an infinite set called A
Subtract three from it.
[ 4, 5, 6, 7…] and say it is called B
Therefore
B-A=3
You can subtract X numbers and keep on going
[X, X+1, X+2, X+3…]
0
#23
Lincoy3304 wrote:
@Knight_king1014,
Infinity is a difficult concept to understand. As we all know, anything plus infinity is infinity.
3+♾️=♾️
If we rearrange this equation by subtracting three from each side, then ♾️=♾️-3
Then subtracting infinity from each side we get
♾️-♾️=3
And you can replace 3 with ANY Real Number. Let’s say any real number equals x.
x+♾️=♾️
♾️=♾️-x
♾️-♾️=-x
This is why arithmetic with infinity is quite forbidden.
Another way to think of it would be with sets.
Let [1, 2, 3, 4…] be an infinite set called A
Subtract three from it.
[ 4, 5, 6, 7…] and say it is called B
Therefore
B-A=3
Infinity is a difficult concept to understand. As we all know, anything plus infinity is infinity.
3+♾️=♾️
If we rearrange this equation by subtracting three from each side, then ♾️=♾️-3
Then subtracting infinity from each side we get
♾️-♾️=3
And you can replace 3 with ANY Real Number. Let’s say any real number equals x.
x+♾️=♾️
♾️=♾️-x
♾️-♾️=-x
This is why arithmetic with infinity is quite forbidden.
Another way to think of it would be with sets.
Let [1, 2, 3, 4…] be an infinite set called A
Subtract three from it.
[ 4, 5, 6, 7…] and say it is called B
Therefore
B-A=3
Thanks again Lincoy.
I don't know what he was talking about. As the reasoning from my posts was logical and demonstrable.
But you must have sympathy for me, because you prevented me from wasting my time, Once Again!
Now how on earth do you selectively subtract a number from only one side of an equation?
You always have to perform the same action to both sides of the equals sign, this is basic algebra we’re taking about here, go back to fifth grade if you need a refresher
You always have to perform the same action to both sides of the equals sign, this is basic algebra we’re taking about here, go back to fifth grade if you need a refresher
You’re acting if there was a third infinity in there somewhere
Let me spell this out
♾️ = ♾️ - X
♾️ = - X + ♾️
Now the challenging part for you lot of folks
♾️ - ♾️ = - X + ♾️ - ♾️
There is no intermediate step, this is all one step.
Results in
0 = - X
Saying anything otherwise means you have no understanding of what you’re talking about and you’re only trying to stroke your ego because you failed your math classes in school!
Let me spell this out
♾️ = ♾️ - X
♾️ = - X + ♾️
Now the challenging part for you lot of folks
♾️ - ♾️ = - X + ♾️ - ♾️
There is no intermediate step, this is all one step.
Results in
0 = - X
Saying anything otherwise means you have no understanding of what you’re talking about and you’re only trying to stroke your ego because you failed your math classes in school!
If you had two infinities of different sizes, which I understand is indeed possible, you’d then use a subscript to denote their different sizes, but, having ♾️ - ♾️, puts in the understanding that the two infinities here are the same exact value, and hence can be cancelled out to zero, anything else is just brain dead stupid
Responding to #1:
You can relabel zero any way shape or form, but it’s still multiplying by zero. Whatever you put in the parentheses is equal to 0. Apparently you forgot PEMDAS. The distributive property SHOULD be done after you simplify everything in the parentheses. However, if you relabel them by x and y then it should still hold, but then we know that x-y=0! (Not factorial)
Any number multiplied by 0 is that number minus itself.
It follows the pattern than y X 2 = y+y
y X 3 = y+y+y
Therefore (y X 3) - (y X 2) = y
By this property, y-y = 0 X y
Relabel y as infinity and they’re the same thing
♾️-♾️=0 X ♾️
You can relabel zero any way shape or form, but it’s still multiplying by zero. Whatever you put in the parentheses is equal to 0. Apparently you forgot PEMDAS. The distributive property SHOULD be done after you simplify everything in the parentheses. However, if you relabel them by x and y then it should still hold, but then we know that x-y=0! (Not factorial)
Any number multiplied by 0 is that number minus itself.
It follows the pattern than y X 2 = y+y
y X 3 = y+y+y
Therefore (y X 3) - (y X 2) = y
By this property, y-y = 0 X y
Relabel y as infinity and they’re the same thing
♾️-♾️=0 X ♾️
@DuelingBanjos
Think of infinity as a set of the value [x, x+1, x+2, x+3…] called A
If you subtract three, it’ll be infinity still [x+3, x+4, x+5, x+6…] called B
Then, if you subtract those two infinities (B-A), all the values will cancel out besides the first three from set A. That would leave [x, x+1, x+3]
Therefore, infinity minus infinity equals 3. But you could do this with any value, not only three. Therefore, if the infinite set is not defined properly, then ♾️-♾️ equals any real value.
You don’t need algebra to prove that
Think of infinity as a set of the value [x, x+1, x+2, x+3…] called A
If you subtract three, it’ll be infinity still [x+3, x+4, x+5, x+6…] called B
Then, if you subtract those two infinities (B-A), all the values will cancel out besides the first three from set A. That would leave [x, x+1, x+3]
Therefore, infinity minus infinity equals 3. But you could do this with any value, not only three. Therefore, if the infinite set is not defined properly, then ♾️-♾️ equals any real value.
You don’t need algebra to prove that
There are an indeterminate from and useless to prove.
0
#31
JomsupVora2020 wrote:
There are an indeterminate from and useless to prove.
What are you saying?
Intellectual_26 wrote:
JomsupVora2020 wrote:
There are an indeterminate from and useless to prove.
What are you saying?
There are 7 indeterminate from in calculus which cannot be find value.
0÷0 , 0⁰ , ∞-∞ , ∞÷∞ , ∞⁰ and 1^∞
Intellectual_26 wrote:
What about 0 x infinity?
oh yeah it also indeterminate from. example.
0×∞ = lim x→0 [ x(5÷x) ] = lim x→0 [ x÷x ] × lim x→0 [ 5 ] = 5
0×∞ = lim x→0 [ x²(1÷x) ] = lim x→0 [ x ] = 0
0×∞ = lim x→0 [ x²(1÷x⁴) ] = lim x→0 [ 1/x² ] = ∞
0
#35
JomsupVora2020 wrote:
Intellectual_26 wrote:
What about 0 x infinity?
oh yeah it also indeterminate from. example.
0×∞ = lim x→0 [ x(5÷x) ] = lim x→0 [ x÷x ] × lim x→0 [ 5 ] = 5
0×∞ = lim x→0 [ x²(1÷x) ] = lim x→0 [ x ] = 0
0×∞ = lim x→0 [ x²(1÷x⁴) ] = lim x→0 [ 1/x² ] = ∞
0^0=0/0, infinity^0=1^infinity=infinity/infinity,
Infinity*0=infinity-infinity
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Add X to each side
♾️=♾️+X
Subtract the right infinity to the left side
♾️-♾️=X