0
But in (0<y<1)
y^infinity, is, 1/infinity !
0.1^infinity = 0.000000000...000001
I think you are wrong
No, you're wrong once more.
Bump
Its -1
(-1)^infinity has infinite real and imaginary solutions
For instance (-1)^(2+infinity) is 1*(-1)^infinity
While (-1)^(infinity+0.5) is ((-1)^infinity))*i
You actuallty got a point
*Actually
I always did, Sir.
If x is less than -1, then x^infinity can equal any complex number.
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0
But in (0<y<1)
y^infinity, is, 1/infinity !