If x^infinity is 0. What is x?

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Avatar of One_Zeroth

0

But in (0<y<1)

y^infinity, is, 1/infinity !

Avatar of SriyoTheGreat

0.1^infinity = 0.000000000...000001

I think you are wrong

Avatar of One_Zeroth
SriyogeshS wrote:

0.1^infinity = 0.000000000...000001

I think you are wrong

No, you're wrong once more.

Avatar of One_Zeroth

Bump

Avatar of RandomPlayer4435

Its -1

Avatar of One_Zeroth
ethan1234321 wrote:

Its -1

(-1)^infinity has infinite real and imaginary solutions

Avatar of One_Zeroth
One_Zeroth wrote:
ethan1234321 wrote:

Its -1

(-1)^infinity has infinite real and imaginary solutions

For instance (-1)^(2+infinity) is 1*(-1)^infinity

While (-1)^(infinity+0.5) is ((-1)^infinity))*i

Avatar of RandomPlayer4435

You actuallty got a point

Avatar of RandomPlayer4435

*Actually

Avatar of One_Zeroth

I always did, Sir.

Avatar of One_Zeroth

If x is less than -1, then x^infinity can equal any complex number.

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