Is 1+i, Greater than 1?

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Avatar of One_Zeroth

We don't know, because i is immeasurable.

However the Closest we can get to surmise it's value is, calculating the absolute value of (1+i). Which is 2^(1/2) !

Avatar of PhantomBeaver
Yea i think it is
Avatar of likecats1
Yes
Avatar of Sliver-WoIf
That’s math
Avatar of Sliver-WoIf
Me sad
Avatar of sapphire_kaleidoscope
One_Zeroth wrote:

We don't know, because i is immeasurable.

However the Closest we can get to surmise it's value is, calculating the absolute value of (1+i). Which is 2^(1/2) !

It depends on how you define magnitude, and absolute value/norm is a perfectly valid and rational way to define it.
Not only that, but it actually makes a ton of sense arithmetically. Obviously, norms don't behave the same way as ordinary real numbers in terms of addition, but they behave well under multiplication and related properties such as inversion, i.e. the norm of a product of complex numbers is the product of their norms, the norm of the inverse of an complex number is the inverse of its norm, etc.

Avatar of One_Zeroth
sapphire_kaleidoscope wrote: One_Zeroth wrote:

We don't know, because i is immeasurable.

However the Closest we can get to surmise it's value is, calculating the absolute value of (1+i). Which is 2^(1/2) !

It depends on how you define magnitude, and absolute value/norm is a perfectly valid and rational way to define it.
Not only that, but it actually makes a ton of sense arithmetically. Obviously, norms don't behave the same way as ordinary real numbers in terms of addition, but they behave well under multiplication and related properties such as inversion, . the norm of a product of complex numbers is the product of their norms, the norm of the inverse of an complex number is the inverse of its norm, etc.

Keep up the Good and Great work @sapphire_kaleidoscope

Avatar of ChessDude009

Finally. Something that makes sense!

I applaud this forum.

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